Representation of a Big Number Without Exponent

What is the maximum value of a double in Java? It is 1.7976931348623157E308, that means 1.7976931348623157 x 10 to the power 308. If we write System.out.println(Double.MAX_VALUE) in a Java program we can get this. Any big number in Java is shown with an exponent field naturally. What to do if we want to see all the digits (without the exponent) of a large number? Do you know, if we show the numbers without exponent how large it is? How many digits there in the above number? Unbelievably the number without exponent field is

179769313486231570814527423731704356798070567525844996598917476803157260780028538760589558632766878171540458953514382464234321326889464182768467546703537516986049910576551282076245490090389328944075868508455133942304583236903222948165808559332123348274797826204144723168738177180919299881250404026184124858368

There are 309 digits here. Can you believe it? But how can I know this? I have just written the following lines of codes in a Java program.

BigDecimal bigDecimal = new BigDecimal(Double.MAX_VALUE);
String allDigits = bigDecimal.toPlainString();
System.out.println(allDigits);

So we can use java.math.BigDecimal for the representation of a big numbers without the exponent field.